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Great Circle route difficulty
#4
I don't use a calculator, I run through the tables or do the basic math.

The procedure as described was the the Lat of the destination is the Declination, the Longitude of destination is the GHA and the assumed lat and long are used with the sight reduction tables in the usual way. The out put is the initial course and Hc which 60(90 - Hc) = distance to destination.

Maybe I'll just try running the two examples in question again. I was pretty tired when I tried before which now that I'm alert, maybe I should have done that before bothering everybody!

Oh to answer, not plotting waypoints, just doing the problem as far as getting initial heading and distance. 

As I said, the routine worked fine for the far destinations but close ones the math didn't work. I was getting values for f in excess of 90° and azimuths all over the place.
I used to be a normal person, then I discovered how to locate myself on this planet using a star.
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Messages In This Thread
Great Circle route difficulty - by BigBill - 04-22-2017, 08:22 PM
RE: Great Circle route difficulty - by BigBill - 04-25-2017, 01:48 PM
RE: Great Circle route difficulty - by BigBill - 04-28-2017, 04:11 PM

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