11-25-2022, 02:30 PM
I'm at a loss to understand how to calculate LHA while sailing in Eastern longitudes.
What I know;
LHA in Eastern longitudes= GHA + ApL (Assumed position longitude) (minus 360° if necessary)
Example;
Date- November 25, 2022
GMT- 10:10:59
ApL= E 025° 45'
GHA= 336° 00.7'
LHA= 336° 00.7' + 25° 45'= 361°45.7' - 360° = 1° 45.7'
But, here's the confusion, LHA in Eastern longitudes is supposed to be rounded up or something like that and I'm not really sure if it is supposed to be rounded up. Information on the web is vague and not explained well enough making too many assumptions. Another possibility is that very few who speak English are sailing, doing CN, in the Eastern hemisphere.
So, my estimate to solve the problem is simply this (tell me if I'm wrong)
Eastern longitudes, LHA= GHA (whole degree's) + ApL (whole degrees) + 1
The problem above could be easily solved like this- LHA= 336° + 25° + 1° (minus 360°) = 2°
Any ideas about this?
What I know;
LHA in Eastern longitudes= GHA + ApL (Assumed position longitude) (minus 360° if necessary)
Example;
Date- November 25, 2022
GMT- 10:10:59
ApL= E 025° 45'
GHA= 336° 00.7'
LHA= 336° 00.7' + 25° 45'= 361°45.7' - 360° = 1° 45.7'
But, here's the confusion, LHA in Eastern longitudes is supposed to be rounded up or something like that and I'm not really sure if it is supposed to be rounded up. Information on the web is vague and not explained well enough making too many assumptions. Another possibility is that very few who speak English are sailing, doing CN, in the Eastern hemisphere.
So, my estimate to solve the problem is simply this (tell me if I'm wrong)
Eastern longitudes, LHA= GHA (whole degree's) + ApL (whole degrees) + 1
The problem above could be easily solved like this- LHA= 336° + 25° + 1° (minus 360°) = 2°
Any ideas about this?