Celestial Nav problem I can't solve

[Fred_B]

Ray,

Here's a quick comment which might initially help getting the correct Ho. The IE is +2.3' which means "it's on the arc" so you "take it off". That is- subtract that figure from Hs. In your calculations the Ho would be 13° 44.2' which is pretty close to Clen's.

I'll look at the remaining portion of above post tomorrow.

Fred